d^2-9de+20e^2=0

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Solution for d^2-9de+20e^2=0 equation:


Simplifying
d2 + -9de + 20e2 = 0

Reorder the terms:
-9de + d2 + 20e2 = 0

Solving
-9de + d2 + 20e2 = 0

Solving for variable 'd'.

Factor a trinomial.
(d + -5e)(d + -4e) = 0

Subproblem 1

Set the factor '(d + -5e)' equal to zero and attempt to solve: Simplifying d + -5e = 0 Solving d + -5e = 0 Move all terms containing d to the left, all other terms to the right. Add '5e' to each side of the equation. d + -5e + 5e = 0 + 5e Combine like terms: -5e + 5e = 0 d + 0 = 0 + 5e d = 0 + 5e Remove the zero: d = 5e Simplifying d = 5e

Subproblem 2

Set the factor '(d + -4e)' equal to zero and attempt to solve: Simplifying d + -4e = 0 Solving d + -4e = 0 Move all terms containing d to the left, all other terms to the right. Add '4e' to each side of the equation. d + -4e + 4e = 0 + 4e Combine like terms: -4e + 4e = 0 d + 0 = 0 + 4e d = 0 + 4e Remove the zero: d = 4e Simplifying d = 4e

Solution

d = {5e, 4e}

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